Equation for parabola from focus and directrix | Conic sections | Algebra II | Khan Academy

Equation for parabola from focus and directrix | Conic sections | Algebra II | Khan Academy


– [Voiceover] What I have
attempted to draw here in yellow is a parabola, and as we’ve already
seen in previous videos, a parabola can be defined
as the set of all points that are equidistant
to a point and a line, and the point is called
the focus of the parabola, and the line is called the
directrix of the parabola. What I want to do in this video, it’s gonna get a little
bit of hairy algebra, but given that definition, I want to see, and given that definition,
and given a focus at the point x equals a, y equals b, and a line, a directrix, at y equals k, to figure out what is the equation of that parabola actually going to be, and it’s going to be based
on a’s, b’s, and k’s, so let’s do that. So let’s take a arbitrary
point on the parabola. Let’s say we take this
point right over here, and its x-coordinate is x,
and its y-coordinate is y, and by definition, in order
for this to be a parabola, it has to be equidistant to
its focus and its directrix, so what does that mean? That means that the
distance to the directrix, which I’m drawing here in blue, has to be the same as the
distance to the focus, which I am drawing in magenta, and when we take the
distance to the directrix, we literally just drop a perpendicular, I guess you could say say, that is, that’s going to be the shortest distance to that line, but the distance to the focus, well we see that’s at a bit of an angle, and we might have to use
the distance formula, which is really just
the Pythagorean Theorem. So let’s do that. This distance has to be
the same as that distance. So, what’s this blue distance? Well, that’s just gonna
be our change in y. It’s going to be this y, minus k. It’s just this distance. So it’s going to be y minus k. Now we have to be careful. The way I’ve just drawn it, yes, y is greater than k, so this is going to give
us a positive value, and you need a non-negative value if you’re talking about distances, but you can definitely
have a parabola where the y-coordinate of the focus is lower than the y-coordinate
of the directrix, in which case this would be negative. So what we really want is
the absolute value of this, or, we could square it, and then we could take the square root, the principle root,
which would be equivalent to taking the absolute value of y minus k. So that’s this distance right over here, and by the definition of a parabola, in order for (x,y) to be
sitting on the parabola, that distance needs to be
the same as the distance from (x,y) to (a,b), to the focus. So what’s that going to be? Well, we just apply the distance formula, or really, just the Pythagorean Theorem. It’s gonna be our change in x, so, x minus a, squared, plus the change in y, y minus b, squared, and the square root of that whole thing, the square root of all of that business. Now, this right over here is
an equation of a parabola. It doesn’t look like it,
it looks really hairy, but it IS the equation of a parabola, and to show you that, we
just have to simplify this, and if you get inspired, I encourage you to try to
simplify this on your own, it’s just gonna be a little
bit of hairy algebra, but it really is not too bad. You’re gonna get an
equation for a parabola that you might recognize, and it’s gonna be in terms
of a general focus, (a,b), and a gerneral directrix, y equals k, so let’s do that. So the simplest thing to start here, is let’s just square both sides, so we get rid of the radicals. So if you square both sides,
on the left-hand side, you’re gonna get y minus k, squared is equal to x minus a, squared, plus y minus b, squared. Fair enough? Now what I want to do
is, I just want to end up with just a y on the left-hand side, and just x’s, ab’s, and
k’s on the right-hand side, so the first thing I might want to do, is let’s expand each of these expressions that involve with y, so this blue one on the left-hand side, that is going to be y squared minus 2yk, plus k squared, and that is going to be equal to, I’m gonna keep this first one the same, so it’s gonna be x minus a, squared, and now let me expand, I’m gonna find a color, expand this in green, so plus y squared, minus
2yb, plus b squared. All I did, is I multiplied
y minus b, times y minus b. Now let’s see if we can simplify things. So, I have a y squared on the left, I have a y squared on the right, well, if I subtract y
squared from both sides, so I can do that. Well, that simplified things a little bit, and now I can, let’s see what I can do. Well let’s get the k squared on this side, so let’s subtract k
squared from both sides, so, subtract k squared from both sides, so that’s gonna get rid of
it on the left-hand side, and now let’s add 2yb to both sides, so we have all the y’s
on the left-hand side, so, plus 2yb, that’s gonna give us a
2yb on the left-hand side, plus 2yb. So what is this going to be equal to? And I’m starting to run into my graph, so let me give myself a little bit more real estate over here. So on the left-hand side, what am I going to have? This is the same thing as 2yb minus 2yk, which is the same thing, actually let me just write that down. That’s going to be 2y– Do it in green, actually,
well, yeah, why not green? That’s going to be– Actually, let me start
a new color. (chuckles) That’s going to be 2yb minus 2yk. You can factor out a 2y, and it’s gonna be 2y times, b minus k. So let’s do that. So we could write this as 2 times, b minus k, y if you factor out a 2 and a y, so that’s the left-hand side, so that’s that piece right over there. These things cancel out. Now, on our right-hand side, I promised you a little
bit of hairy algebra, so hopefully you see that I’m
delivering on that promise. On the right-hand side, you have x minus a, squared, and then, let’s see, these
characters cancel out, and you’re left with b
squared minus k squared, so these two are gonna be
b squared minus k squared, plus b squared minus k squared. Now, I said all I want is
a y on the left-hand side, so let’s divide everything
by two times, b minus k. So, let’s divide everything, two times, b minus k, so, two times, b minus k. And I’m actually gonna
divide this whole thing by two times, b minus k. Now, obviously on the left-hand side, this all cancels out,
you’re left with just a y, and then it’s going to be y equals, y is equal to one over, two times, b minus k, and notice, b minus k is the difference between the y-coordinate of the focus, and the y-coordinate,
I guess you could say, of the line, y equals k, so it’s one over, two times that, times x minus a, squared. So if you knew what b minus k was, this would just simplify to some number, some number that’s being multiplied times x minus a, squared, so hopefully this is starting
to look like the parabolas that you remember from
your childhood, (chuckles) if you do remember parabolas
from your childhood. Alright, so then let’s see if we could simplify this thing on the right, and you might recognize,
b squared minus k squared, that’s a difference of squares, that’s the same thing as b plus k, times b minus k, so the b minus k’s cancel out, and we are just left with, and we deserve a little
bit of a drum roll, we are just left with 1/2 times, b plus k. So, there you go. Given a focus at a point (a,b), and a directrix at y equals k, we now know what the
formula of the parabola is actually going to be. So, for example, if I had a focus at the point, I don’t know, let’s say the point (1,2), and I had a directrix at y is equal to, I don’t know, let’s make it y is equal to -1, what would the equation
of this parabola be? Well, it would be y is equal to one over, two times, b minus k, so two minus -1, that’s the same thing as two plus one, so that’s just three, two minus -1 is three, times x minus one, squared, plus 1/2 times, b plus k. Two plus -1 is one, so one, and so what is this going to be? You’re gonna get y is equal to 1/6, x minus one, squared, plus 1/2. There you go. That is the parabola with a focus at (1,2) and a directrix at y equals -1. Fascinating.

47 thoughts on “Equation for parabola from focus and directrix | Conic sections | Algebra II | Khan Academy

  1. Everytime I struggle with my algebra, I come here. I do online school so it's hard to move forward when I'm stuck without my teacher getting back to me (especially since I'm a night owl. I normally have to wait until the following day). Thank you! I'm bad with numbers but when I watch these videos they (sort of) make sense.

  2. When you're in high school, and you're asking yourself, "when am I ever gonna need to know this?" That time is grad school. I never throught I would have to revisit precalc to find the arc length of a cable on a suspension bridge

  3. A parabola is defined as the locus of points that are equidistant from both the directrix and the focus in a coordinate plane. … the math (the derivation of the general form of the equation of a parabola) follows from that definition.  It is simple IF you begin with the correct definition.

  4. How do I find the equation of the ellipse given only that the the major axis is vertical and the graph passes through the vertex of a parabola?

  5. How do we find the focus or the directrix when the vertex is (4,0) and solving for y=? I can’t find anywhere that answers this. My question is to find if there is a minimum or maximum of the equation y=(x+4)squared.

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